3(x^2+5)=-3x^2+2x+5

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Solution for 3(x^2+5)=-3x^2+2x+5 equation:



3(x^2+5)=-3x^2+2x+5
We move all terms to the left:
3(x^2+5)-(-3x^2+2x+5)=0
We multiply parentheses
-(-3x^2+2x+5)+3x^2+15=0
We get rid of parentheses
3x^2+3x^2-2x-5+15=0
We add all the numbers together, and all the variables
6x^2-2x+10=0
a = 6; b = -2; c = +10;
Δ = b2-4ac
Δ = -22-4·6·10
Δ = -236
Delta is less than zero, so there is no solution for the equation

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